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0=y^2-90
We move all terms to the left:
0-(y^2-90)=0
We add all the numbers together, and all the variables
-(y^2-90)=0
We get rid of parentheses
-y^2+90=0
We add all the numbers together, and all the variables
-1y^2+90=0
a = -1; b = 0; c = +90;
Δ = b2-4ac
Δ = 02-4·(-1)·90
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{10}}{2*-1}=\frac{0-6\sqrt{10}}{-2} =-\frac{6\sqrt{10}}{-2} =-\frac{3\sqrt{10}}{-1} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{10}}{2*-1}=\frac{0+6\sqrt{10}}{-2} =\frac{6\sqrt{10}}{-2} =\frac{3\sqrt{10}}{-1} $
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